What is 4*pi*1*10^3*22*10^{-9}*47*10^{-9} ?

The solution to 4*pi*1*10^3*22*10^{-9}*47*10^{-9} is (517pi)/(5^{15)*4096}

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simplify 4pi1*10^32210^{-9}4710^{-9}

simplify

4 \cdot π \cdot 1 \cdot 1 0^{3} \cdot 22 \cdot 1 0^{- 9} \cdot 47 \cdot 1 0^{- 9}

\frac{517 π}{5 ^{15} \cdot 4096}

Decimal Notation

1.29936 E - 11

Solution steps

4 π 1 \cdot 1 0^{3} \cdot 22 \cdot 1 0^{- 9} \cdot 47 \cdot 1 0^{- 9}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

1 0^{3} \cdot 1 0^{- 9} \cdot 1 0^{- 9} = 1 0^{3 - 9 - 9}

= 4 π 1 \cdot 22 \cdot 47 \cdot 1 0^{3 - 9 - 9}

Subtract the numbers:

3 - 9 - 9 = - 15

= 4 π 1 \cdot 22 \cdot 47 \cdot 1 0^{- 15}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 15} = \frac{1}{1 0 ^{15}}

= 4 \cdot 1 \cdot 22 \cdot 47 π \frac{1}{1 0 ^{15}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= 1 \cdot \frac{1 \cdot 4 \cdot 22 \cdot 47 π}{1 0 ^{15}}

\frac{1 \cdot 4 π 22 \cdot 47}{1 0 ^{15}} = \frac{517 π}{5 ^{15} \cdot 4096}

= 1 \cdot \frac{517 π}{5 ^{15} \cdot 4096}

Multiply:

1 \cdot \frac{517 π}{5 ^{15} \cdot 4096} = \frac{517 π}{5 ^{15} \cdot 4096}

= \frac{517 π}{5 ^{15} \cdot 4096}

9.32 \times 1 0^{- 10}

e^{\frac{1}{2}} \cdot 2 e^{2} \cdot 5 e^{3}

(x^{2} + (y - 1)^{2}) \cdot x^{2} + (y + 1)^{2}

What is 4*pi*1*10^3*22*10^{-9}*47*10^{-9} ?
The solution to 4*pi*1*10^3*22*10^{-9}*47*10^{-9} is (517pi)/(5^{15)*4096}