What are the solutions to the equation 2x^2+x=3 ?

The solutions to the equation 2x^2+x=3 are x=1,x=-3/2

Find the zeros of 2x^2+x=3

The zeros of 2x^2+x=3 are x=1,x=-3/2

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2 x^{2} + x = 3

x = 1, x = - \frac{3}{2}

Solution steps

2 x^{2} + x = 3

Move

3

to the left side

2 x^{2} + x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 3) = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 \cdot 2}, x_{2} = \frac{- 1 - 5}{2 \cdot 2}

x = \frac{- 1 + 5}{2 \cdot 2} : 1

x = \frac{- 1 - 5}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = 1, x = - \frac{3}{2}

\frac{x - 3}{x + 3} < 2 x - 1

∣ 9 - 4 x ∣ > 16

\frac{1}{2} x - 4 = - 3 - \frac{1}{3} x

4 x^{2} + 25 x + 6

\frac{2}{5} \cdot 10 + 3 \cdot 6 - 6

What are the solutions to the equation 2x^2+x=3 ?
The solutions to the equation 2x^2+x=3 are x=1,x=-3/2
Find the zeros of 2x^2+x=3
The zeros of 2x^2+x=3 are x=1,x=-3/2