What is log_{10}(x)(x^2+1)^{-1/2} ?

The solution to log_{10}(x)(x^2+1)^{-1/2} is (log_{10}(x))/((x^2+1)^{1/2)}

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simplify log_{10}(x)(x^2+1)^{-1/2}

simplify

lo g_{10} (x) (x^{2} + 1)^{- \frac{1}{2}}

\frac{lo g _{10} ( x )}{( x ^{2} + 1 ) ^{\frac{1}{2}}}

Solution steps

lo g_{10} (x) (x^{2} + 1)^{- \frac{1}{2}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(x^{2} + 1)^{- \frac{1}{2}} = \frac{1}{( x ^{2} + 1 ) ^{\frac{1}{2}}}

= lo g_{10} (x) \frac{1}{( x ^{2} + 1 ) ^{\frac{1}{2}}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{lo g _{10} ( x ) \cdot 1}{( x ^{2} + 1 ) ^{\frac{1}{2}}}

Apply rule:

a \cdot 1 = a

lo g_{10} (x) \cdot 1 = lo g_{10} (x)

= \frac{lo g _{10} ( x )}{( x ^{2} + 1 ) ^{\frac{1}{2}}}

7.26 \cdot e^{- \frac{9.4}{0.74}}

e^{- 3.45}

- 2 e^{- 6}

e^{- 3.42}

e^{- 3.33}

What is log_{10}(x)(x^2+1)^{-1/2} ?
The solution to log_{10}(x)(x^2+1)^{-1/2} is (log_{10}(x))/((x^2+1)^{1/2)}