What is (a^2b^{-7})/(a^{-4)b^{-2}} ?

The solution to (a^2b^{-7})/(a^{-4)b^{-2}} is (a^6)/(b^5)

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simplify (a^2b^{-7})/(a^{-4)b^{-2}}

simplify

\frac{a ^{2} b ^{- 7}}{a ^{- 4} b ^{- 2}}

\frac{a ^{6}}{b ^{5}}

Solution steps

\frac{a ^{2} b ^{- 7}}{a ^{- 4} b ^{- 2}}

Simplify

\frac{a ^{2}}{a ^{- 4}} : a^{6}

= \frac{a ^{6} b ^{- 7}}{b ^{- 2}}

Simplify

\frac{b ^{- 7}}{b ^{- 2}} : \frac{1}{b ^{5}}

= \frac{a ^{6}}{b ^{5}}

(\frac{1}{16})^{\frac{1}{4}}

13 x + 7 = 5 x - 20

12 x^{2} - 16 x + 24

(\frac{x ^{5}}{- 2})^{- 3}

8 - x < - 2 (x + 10)

What is (a^2b^{-7})/(a^{-4)b^{-2}} ?
The solution to (a^2b^{-7})/(a^{-4)b^{-2}} is (a^6)/(b^5)