What is (2x^2yz)(3xyz^2) ?

The solution to (2x^2yz)(3xyz^2) is 6x^3y^2z^3

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simplify (2x^2yz)(3xyz^2)

simplify

(2 x^{2} yz) (3 x y z^{2})

6 x^{3} y^{2} z^{3}

Solution steps

(2 x^{2} yz) (3 x y z^{2})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x^{2} x = x^{2 + 1}

= 2 yz \cdot 3 x^{2 + 1} y z^{2}

Add the numbers:

2 + 1 = 3

= 2 yz \cdot 3 x^{3} y z^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

yy = y^{1 + 1}

= 2 z \cdot 3 x^{3} y^{1 + 1} z^{2}

Add the numbers:

1 + 1 = 2

= 2 z \cdot 3 x^{3} y^{2} z^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

z z^{2} = z^{1 + 2}

= 2 \cdot 3 x^{3} y^{2} z^{1 + 2}

Add the numbers:

1 + 2 = 3

= 2 \cdot 3 x^{3} y^{2} z^{3}

Multiply the numbers:

2 \cdot 3 = 6

= 6 x^{3} y^{2} z^{3}

(4 m^{8}) (16 n^{8})

(3 - x)^{- 2}

(x - 2) (x - 2)

\frac{( - 9 ) ^{5}}{9 ^{- 5}} \cdot ((- 9)^{3})^{- 3}

3.2 \cdot 1 0^{- 19} \cdot 400