What are the solutions to the equation 9x^2+4x-2=0 ?

The solutions to the equation 9x^2+4x-2=0 are x=(-2+sqrt(22))/9 ,x=-(2+sqrt(22))/9

Find the zeros of 9x^2+4x-2=0

The zeros of 9x^2+4x-2=0 are x=(-2+sqrt(22))/9 ,x=-(2+sqrt(22))/9

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9 x^{2} + 4 x - 2 = 0

x = \frac{- 2 + 22}{9}, x = - \frac{2 + 22}{9}

Solution steps

9 x^{2} + 4 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 9 ( - 2 )}{2 \cdot 9}

4^{2} - 4 \cdot 9 (- 2) = 222

x_{1, 2} = \frac{- 4 \pm 2 22}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 4 + 2 22}{2 \cdot 9}, x_{2} = \frac{- 4 - 2 22}{2 \cdot 9}

x = \frac{- 4 + 2 22}{2 \cdot 9} : \frac{- 2 + 22}{9}

x = \frac{- 4 - 2 22}{2 \cdot 9} : - \frac{2 + 22}{9}

The solutions to the quadratic equation are:

x = \frac{- 2 + 22}{9}, x = - \frac{2 + 22}{9}

\frac{3 m ^{3} n ^{2}}{8 m ^{9} n ^{12}}

3^{k - 1} + 3^{k}

- 1 - 7 m = - 8 m + 7

41.8 (x - 2.7) + \frac{1}{2} 9.8 (x^{2} - (x - 2.7)) = 89

- \frac{1}{6} b = 3

What are the solutions to the equation 9x^2+4x-2=0 ?
The solutions to the equation 9x^2+4x-2=0 are x=(-2+sqrt(22))/9 ,x=-(2+sqrt(22))/9
Find the zeros of 9x^2+4x-2=0
The zeros of 9x^2+4x-2=0 are x=(-2+sqrt(22))/9 ,x=-(2+sqrt(22))/9