What is x^2(x+1)^2(2x^2+2x+1)(2x^2-2x+1) ?

The solution to x^2(x+1)^2(2x^2+2x+1)(2x^2-2x+1) is x^2(x+1)^2(2x^2+2x+1)(2x^2-2x+1)

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simplify x^2(x+1)^2(2x^2+2x+1)(2x^2-2x+1)

simplify

x^{2} (x + 1)^{2} (2 x^{2} + 2 x + 1) (2 x^{2} - 2 x + 1)

x^{2} (x + 1)^{2} (2 x^{2} + 2 x + 1) (2 x^{2} - 2 x + 1)

Solution steps

x^{2} (x + 1)^{2} (2 x^{2} + 2 x + 1) (2 x^{2} - 2 x + 1)

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

x^{2} (x + 1)^{2} = (x (x + 1))^{2}

= (x (x + 1))^{2} (2 x^{2} + 2 x + 1) (2 x^{2} - 2 x + 1)

(x (x + 1))^{2} = x^{2} (x + 1)^{2}

= x^{2} (x + 1)^{2} (2 x^{2} + 2 x + 1) (2 x^{2} - 2 x + 1)

(3)^{2} \cdot 3

- e^{(- 1)}

2 x (x)^{3}

(125)^{3}

What is x^2(x+1)^2(2x^2+2x+1)(2x^2-2x+1) ?
The solution to x^2(x+1)^2(2x^2+2x+1)(2x^2-2x+1) is x^2(x+1)^2(2x^2+2x+1)(2x^2-2x+1)