What is \det(8+j^8)(j^2)(j^2)(4-j^4) ?

The solution to \det(8+j^8)(j^2)(j^2)(4-j^4) is j^4\det(j^8+8)(-j^4+4)

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simplify \det(8+j^8)(j^2)(j^2)(4-j^4)

simplify

det (8 + j^{8}) (j^{2}) (j^{2}) (4 - j^{4})

j^{4} det (j^{8} + 8) (- j^{4} + 4)

Solution steps

det (8 + j^{8}) (j^{2}) (j^{2}) (4 - j^{4})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

j^{2} j^{2} = j^{2 + 2}

= det (8 + j^{8}) j^{2 + 2} (4 - j^{4})

Add the numbers:

2 + 2 = 4

= det (8 + j^{8}) j^{4} (4 - j^{4})

x + 3 x + 6

(e^{- 2 x}) (e^{x})

440 \cdot 10 \cdot 1 0^{23} \cdot (π \cdot (0.1 \cdot 1 0^{- 3})^{2})

(5 d^{8} e^{2}) (9 d^{- 4} e^{- 2})

What is \det(8+j^8)(j^2)(j^2)(4-j^4) ?
The solution to \det(8+j^8)(j^2)(j^2)(4-j^4) is j^4\det(j^8+8)(-j^4+4)