What is (e^{-2x})(1/(1+e^x)) ?

The solution to (e^{-2x})(1/(1+e^x)) is 1/(e^{2x)(e^x+1)}

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simplify (e^{-2x})(1/(1+e^x))

simplify

(e^{- 2 x}) (\frac{1}{1 + e ^{x}})

\frac{1}{e ^{2 x} ( e ^{x} + 1 )}

Solution steps

(e^{- 2 x}) (\frac{1}{1 + e ^{x}})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{2 x}} \cdot \frac{1}{e ^{x} + 1}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot 1}{e ^{2 x} ( 1 + e ^{x} )}

Multiply the numbers:

1 \cdot 1 = 1

= \frac{1}{e ^{2 x} ( e ^{x} + 1 )}

e^{- 5 l n (x)}

\frac{3 y}{2}

0.9 \times 1 0^{- 1}

What is (e^{-2x})(1/(1+e^x)) ?
The solution to (e^{-2x})(1/(1+e^x)) is 1/(e^{2x)(e^x+1)}