What is (sqrt(3))^{1-x}*9^{1-2x} ?

The solution to (sqrt(3))^{1-x}*9^{1-2x} is 3^{(-9x+1)/2+2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (sqrt(3))^{1-x}*9^{1-2x}

simplify

(3)^{1 - x} \cdot 9^{1 - 2 x}

3^{\frac{- 9 x + 1}{2} + 2}

Solution steps

(3)^{1 - x} \cdot 9^{1 - 2 x}

(3)^{1 - x} : 3^{\frac{1 - x}{2}}

= 3^{\frac{1 - x}{2}} \cdot 9^{1 - 2 x}

Factor integer

9 = 3^{2}

= 3^{\frac{1 - x}{2}} (3^{2})^{1 - 2 x}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

(3^{2})^{1 - 2 x} = 3^{2 (1 - 2 x)}

= 3^{\frac{1 - x}{2}} \cdot 3^{2 (1 - 2 x)}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

3^{\frac{1 - x}{2}} \cdot 3^{2 (1 - 2 x)} = 3^{\frac{- x + 1}{2} + 2 (- 2 x + 1)}

= 3^{\frac{1 - x}{2} + 2 (1 - 2 x)}

Expand

\frac{1 - x}{2} + 2 (1 - 2 x) : \frac{1 - 9 x}{2} + 2

= 3^{\frac{- 9 x + 1}{2} + 2}

2 e^{- y}

(25 - y^{2})^{2}

3.8 \cdot 1 0^{- 3}

25 e^{- 1.35}

What is (sqrt(3))^{1-x}*9^{1-2x} ?
The solution to (sqrt(3))^{1-x}*9^{1-2x} is 3^{(-9x+1)/2+2}