What is (x^2-x+1)^2(2x^3-5)^2 ?

The solution to (x^2-x+1)^2(2x^3-5)^2 is (2x^3-5)^2(x^2-x+1)^2

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simplify (x^2-x+1)^2(2x^3-5)^2

simplify

(x^{2} - x + 1)^{2} (2 x^{3} - 5)^{2}

(2 x^{3} - 5)^{2} (x^{2} - x + 1)^{2}

Solution steps

(x^{2} - x + 1)^{2} (2 x^{3} - 5)^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(x^{2} - x + 1)^{2} (2 x^{3} - 5)^{2} = ((x^{2} - x + 1) (2 x^{3} - 5))^{2}

= ((x^{2} - x + 1) (2 x^{3} - 5))^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= (x^{2} - x + 1)^{2} (2 x^{3} - 5)^{2}

\frac{x - 1}{x}

(π)^{2}

\frac{30 ( x - 1 )}{5 ( x - 1 ) ^{2}}

x e^{- (\frac{x}{2})^{2}}

What is (x^2-x+1)^2(2x^3-5)^2 ?
The solution to (x^2-x+1)^2(2x^3-5)^2 is (2x^3-5)^2(x^2-x+1)^2