What is \sqrt[4]{z^{-6}}z^{18} ?

The solution to \sqrt[4]{z^{-6}}z^{18} is z^{16}sqrt(z)

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simplify \sqrt[4]{z^{-6}}z^{18}

simplify

z^{16} z

Solution steps

Simplify

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

Apply rule:

1 \cdot a = a

1 \cdot z^{18} = z^{18}

Simplify

\frac{z ^{18}}{z} : z^{17}

Simplify

= \frac{z ^{17}}{z ^{\frac{1}{2}}}

Simplify

\frac{z ^{17}}{z ^{\frac{1}{2}}} : z^{16} z

= z^{16} z

e^{- 3 y}

((\frac{1}{2})^{3})^{0}^{- 2}

e^{(- 8 t)} \cdot cosh (4 t)

\frac{n + 2}{n + 1}

1.19 \cdot 1 0^{- 7}

What is \sqrt[4]{z^{-6}}z^{18} ?
The solution to \sqrt[4]{z^{-6}}z^{18} is z^{16}sqrt(z)