What is (4.1*10^{-2})(2*10^{-1}) ?

The solution to (4.1*10^{-2})(2*10^{-1}) is 0.0082

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simplify (4.110^{-2})(210^{-1})

simplify

(4.1 \cdot 1 0^{- 2}) (2 \cdot 1 0^{- 1})

0.0082

Solution steps

(4.1 \cdot 1 0^{- 2}) (2 \cdot 1 0^{- 1})

Simplify

4.1 \cdot 1 0^{- 2} : 0.041

= 0.041 \cdot 2 \cdot 1 0^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

1 0^{- 1} = \frac{1}{10}

= 0.041 \cdot 2 \cdot \frac{1}{10}

Multiply the numbers:

0.041 \cdot 2 = 0.082

= 0.082 \cdot \frac{1}{10}

= \frac{1}{10} \cdot 0.082

\frac{1}{10} \cdot 0.082 = \frac{0.082}{10}

= \frac{0.082}{10}

Divide the numbers:

\frac{0.082}{10} = 0.0082

= 0.0082

0.03 \cdot 1 0^{- 3}

e^{- \frac{300}{200}}

What is (4.1*10^{-2})(2*10^{-1}) ?
The solution to (4.1*10^{-2})(2*10^{-1}) is 0.0082