What is (64x^4)^{0.5}\times 4x^{-2} ?

The solution to (64x^4)^{0.5}\times 4x^{-2} is 32

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simplify (64x^4)^{0.5}\times 4x^{-2}

simplify

(64 x^{4})^{0.5} \cdot 4 x^{- 2}

32

Solution steps

(64 x^{4})^{0.5} \cdot 4 x^{- 2}

Simplify

(64 x^{4})^{0.5} : 8 x^{2}

= 8 x^{2} \cdot 4 x^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

x^{- 2} = \frac{1}{x ^{2}}

= 8 x^{2} \cdot 4 \cdot \frac{1}{x ^{2}}

Multiply the numbers:

8 \cdot 4 = 32

= 32 x^{2} \frac{1}{x ^{2}}

Cross-cancel common factor:

x^{2}

= 32

3 (- 1) e^{- 1}

- 12 (10) e^{- 0.1 (10)}

(100 - p)^{2}

(s + 0.5989 + j^{0.868}) (s + 0.5989 + j^{0.868})

(x + 1)^{2} (x - 1)^{2} (x^{2} + 1 + x)^{2} (x^{2} + 1 - x)^{2}

What is (64x^4)^{0.5}\times 4x^{-2} ?
The solution to (64x^4)^{0.5}\times 4x^{-2} is 32