What is e^{-3}*(3^2)/(2!) ?

The solution to e^{-3}*(3^2)/(2!) is 9/(2e^3)

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simplify e^{-3}*(3^2)/(2!)

simplify

e^{- 3} \cdot \frac{3 ^{2}}{2 !}

\frac{9}{2 e ^{3}}

Decimal Notation

0.22404 \dots

Solution steps

e^{- 3} \frac{3 ^{2}}{2 !}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{3}} \cdot \frac{3 ^{2}}{2 !}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot 3 ^{2}}{e ^{3} \cdot 2 !}

Multiply:

1 \cdot 3^{2} = 3^{2}

= \frac{3 ^{2}}{e ^{3} \cdot 2 !}

3^{2} = 9

= \frac{9}{e ^{3} \cdot 2 !}

e^{3} \cdot 2! = 2 e^{3}

= \frac{9}{2 e ^{3}}

e^{- π \cdot \frac{0.24065}{1 - 0.2406 5 ^{2}}}

3^{3}

6.6667 x 1 0^{- 11} x \frac{5.98 x 1 0 ^{- 11}}{( 6400 + 700 ) ^{2}}

(1.013 \cdot 1 0^{5}) (0.1 \cdot 0.1)

(e^{- t})^{2}