What is (x-1)^2(x-3)^2(x+4)^2 ?

The solution to (x-1)^2(x-3)^2(x+4)^2 is (x-1)^2(x-3)^2(x+4)^2

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simplify (x-1)^2(x-3)^2(x+4)^2

simplify

(x - 1)^{2} (x - 3)^{2} (x + 4)^{2}

(x - 1)^{2} (x - 3)^{2} (x + 4)^{2}

Solution steps

(x - 1)^{2} (x - 3)^{2} (x + 4)^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(x - 1)^{2} (x - 3)^{2} (x + 4)^{2} = ((x - 1) (x - 3) (x + 4))^{2}

= ((x - 1) (x - 3) (x + 4))^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= (x - 1)^{2} (x - 3)^{2} (x + 4)^{2}

(6.674 \cdot 1 0^{- 11}) (6 \cdot 1 0^{24})

1 - x^{3}

(3 + 2 - 1) (3 + 2 - 1)

x^{2} e^{- x}

What is (x-1)^2(x-3)^2(x+4)^2 ?
The solution to (x-1)^2(x-3)^2(x+4)^2 is (x-1)^2(x-3)^2(x+4)^2