What is (f\circ f^{-1})(-10) ?

The solution to (f\circ f^{-1})(-10) is -10\circ

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simplify (f\circ f^{-1})(-10)

simplify

(f \circ f^{- 1}) (- 10)

- 10 \circ

Decimal Notation

- 10

Solution steps

(f \circ f^{- 1}) (- 10)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

f f^{- 1} = f^{1 - 1}

= \circ f^{1 - 1} (- 10)

Subtract the numbers:

1 - 1 = 0

= \circ f^{0} (- 10)

Apply rule

a^{0} = 1, a \neq = 0

f^{0} = 1

= 1 \cdot (- 10) \circ

Remove parentheses:

(- a) = - a

= - \circ 1 \cdot 10

Multiply the numbers:

1 \cdot 10 = 10

= - 10 \circ

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