What is ((-1/3)-1)/(2(-1/3)^2-(-1/3)) ?

The solution to ((-1/3)-1)/(2(-1/3)^2-(-1/3)) is -12/5

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simplify ((-1/3)-1)/(2(-1/3)^2-(-1/3))

simplify

\frac{( - \frac{1}{3} ) - 1}{2 ( - \frac{1}{3} ) ^{2} - ( - \frac{1}{3} )}

- \frac{12}{5}

Solution steps

\frac{( - \frac{1}{3} ) - 1}{2 ( - \frac{1}{3} ) ^{2} - ( - \frac{1}{3} )}

\frac{( - \frac{1}{3} ) - 1}{2 ( - \frac{1}{3} ) ^{2} - ( - \frac{1}{3} )} = \frac{- \frac{1}{3} - 1}{2 ( - \frac{1}{3} ) ^{2} + \frac{1}{3}}

= \frac{- \frac{1}{3} - 1}{2 ( - \frac{1}{3} ) ^{2} + \frac{1}{3}}

- \frac{1}{3} - 1 = - \frac{4}{3}

= \frac{- \frac{4}{3}}{2 ( - \frac{1}{3} ) ^{2} + \frac{1}{3}}

2 (- \frac{1}{3})^{2} + \frac{1}{3} = \frac{5}{9}

= \frac{- \frac{4}{3}}{\frac{5}{9}}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{\frac{4}{3}}{\frac{5}{9}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

\frac{\frac{4}{3}}{\frac{5}{9}} = \frac{4 \cdot 9}{3 \cdot 5}

= - \frac{4 \cdot 9}{3 \cdot 5}

Cancel

- \frac{4 \cdot 9}{3 \cdot 5} : - \frac{12}{5}

= - \frac{12}{5}

(\frac{1}{2})^{12}

7 (2 x - 1) = 5 (x + 6) - 13

4 p^{2} + 3 = 4 p

7^{2}

9 x^{2} - 12 x > - 4

What is ((-1/3)-1)/(2(-1/3)^2-(-1/3)) ?
The solution to ((-1/3)-1)/(2(-1/3)^2-(-1/3)) is -12/5