What is 2(λe^{-λt})(1-e^{-λt}) ?

The solution to 2(λe^{-λt})(1-e^{-λt}) is (2λ(-e^{-λt}+1))/(e^{λt)}

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simplify 2(λe^{-λt})(1-e^{-λt})

simplify

2 (λ e^{- λ t}) (1 - e^{- λ t})

\frac{2 λ ( - e ^{- λ t} + 1 )}{e ^{λ t}}

Solution steps

2 (λ e^{- λ t}) (1 - e^{- λ t})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= 2 λ \frac{1}{e ^{λ t}} (- e^{- λ t} + 1)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2 λ ( 1 - e ^{- λ t} )}{e ^{λ t}}

Multiply the numbers:

1 \cdot 2 = 2

= \frac{2 λ ( - e ^{- λ t} + 1 )}{e ^{λ t}}

2.6 \cdot 1 0^{- 5}

2.6 \cdot 1 0^{- 3}

(e^{2 x^{3}})^{2}

- 20 - 10 10

1.785 \cdot 1 0^{- 5}

What is 2(λe^{-λt})(1-e^{-λt}) ?
The solution to 2(λe^{-λt})(1-e^{-λt}) is (2λ(-e^{-λt}+1))/(e^{λt)}