What is \sqrt[3]{2^{1/2 x^2+1}} ?

The solution to \sqrt[3]{2^{1/2 x^2+1}} is 2^{(x^2+2)/6}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify \sqrt[3]{2^{1/2 x^2+1}}

simplify

2^{\frac{x ^{2} + 2}{6}}

Solution steps

Apply radical rule:

= (2^{\frac{1}{2} x^{2} + 1})^{\frac{1}{3}}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 2^{(\frac{1}{2} x^{2} + 1) \frac{1}{3}}

Simplify

(\frac{1}{2} x^{2} + 1) \frac{1}{3} : \frac{x ^{2} + 2}{6}

= 2^{\frac{x ^{2} + 2}{6}}

2 x^{^{'}}

\frac{22}{3}

What is \sqrt[3]{2^{1/2 x^2+1}} ?
The solution to \sqrt[3]{2^{1/2 x^2+1}} is 2^{(x^2+2)/6}