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Popular >

simplify terrell^'s

Solution

simplify

t erre l l^{^{'}} s

Solution

e^{2} l^{' + 1} t r^{2} s

Solution steps

t erre l l^{^{'}} s

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

l l^{^{'}} = l^{1 +^{'}}

= t erre l^{1 +^{^{'}}} s

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

ee = e^{1 + 1}

= t rr e^{1 + 1} l^{1 +^{^{'}}} s

Add the numbers:

1 + 1 = 2

= t rr e^{2} l^{1 +^{^{'}}} s

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

rr = r^{1 + 1}

= t r^{1 + 1} e^{2} l^{1 +^{^{'}}} s

Add the numbers:

1 + 1 = 2

= t r^{2} e^{2} l^{1 +^{^{'}}} s

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Frequently Asked Questions (FAQ)

What is terrell^'s ?
The solution to terrell^'s is e^2l^{'+1}tr^2s