What is (ln(c^{-4}))(ln(a/(b^2)))^{-4} ?

The solution to (ln(c^{-4}))(ln(a/(b^2)))^{-4} is -(4ln(c))/((ln(a)-2ln(b))^4)

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simplify (ln(c^{-4}))(ln(a/(b^2)))^{-4}

simplify

(ln (c^{- 4})) (ln (\frac{a}{b ^{2}}))^{- 4}

- \frac{4 ln ( c )}{( ln ( a ) - 2 ln ( b ) ) ^{4}}

Solution steps

(ln (c^{- 4})) (ln (\frac{a}{b ^{2}}))^{- 4}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{( ln ( \frac{a}{b ^{2}} ) ) ^{4}} ln (c^{- 4})

Simplify

ln (c^{- 4}) : - 4 ln (c)

= - 4 \cdot \frac{1}{ln ^{4} ( \frac{a}{b ^{2}} )} ln (c)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{1 \cdot 4 ln ( c )}{ln ^{4} ( \frac{a}{b ^{2}} )}

Multiply the numbers:

1 \cdot 4 = 4

= - \frac{4 ln ( c )}{ln ^{4} ( \frac{a}{b ^{2}} )}

ln^{4} (\frac{a}{b ^{2}}) = (ln (a) - 2 ln (b))^{4}

= - \frac{4 ln ( c )}{( ln ( a ) - 2 ln ( b ) ) ^{4}}

(2 x^{2}) \cdot x^{3}

- 7 y^{4} (3 x^{2} y^{3})

e^{- 1.1} (\frac{( 1.1 ) ^{0}}{0 !})

What is (ln(c^{-4}))(ln(a/(b^2)))^{-4} ?
The solution to (ln(c^{-4}))(ln(a/(b^2)))^{-4} is -(4ln(c))/((ln(a)-2ln(b))^4)