What is simplify-2.18*10^{-18}(1/(2^2)-1/(5^2)) ?

The solution to simplify-2.18*10^{-18}(1/(2^2)-1/(5^2)) is -(2289)/(5000*10^{18)}

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simplify-2.18*10^{-18}(1/(2^2)-1/(5^2))

simplify

- 2.18 \cdot 1 0^{- 18} (\frac{1}{2 ^{2}} - \frac{1}{5 ^{2}})

- \frac{2289}{5000 \cdot 1 0 ^{18}}

Decimal Notation

0

Solution steps

- 2.18 \cdot 1 0^{- 18} (\frac{1}{2 ^{2}} - \frac{1}{5 ^{2}})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 18} = \frac{1}{1 0 ^{18}}

= - 2.18 \cdot \frac{1}{1 0 ^{18}} (\frac{1}{2 ^{2}} - \frac{1}{5 ^{2}})

\frac{1}{2 ^{2}} - \frac{1}{5 ^{2}} = \frac{21}{100}

= - 2.18 \cdot \frac{1}{1 0 ^{18}} \cdot \frac{21}{100}

- 2.18 \cdot \frac{1}{1 0 ^{18}} \cdot \frac{21}{100} = - \frac{45.78}{1 0 ^{18} \cdot 100}

= - \frac{45.78}{1 0 ^{18} \cdot 100}

\frac{45.78}{1 0 ^{18} \cdot 100} = \frac{4578}{10000 \cdot 1 0 ^{18}}

= - \frac{4578}{10000 \cdot 1 0 ^{18}}

Factor the number:

4578 = 2 \cdot 2289

= - \frac{2 \cdot 2289}{10000 \cdot 1 0 ^{18}}

Factor the number:

10000 = 2 \cdot 5000

= - \frac{2 \cdot 2289}{2 \cdot 5000 \cdot 1 0 ^{18}}

Cancel the common factor:

2

= - \frac{2289}{5000 \cdot 1 0 ^{18}}

\frac{n}{n + i}

x^{2 \circ} x^{2}

(4 7^{5^{n} + 3})^{(\frac{16}{7})^{5^{n}}}

What is simplify-2.18*10^{-18}(1/(2^2)-1/(5^2)) ?
The solution to simplify-2.18*10^{-18}(1/(2^2)-1/(5^2)) is -(2289)/(5000*10^{18)}