What is (\sqrt[6]{sqrt(s^{24)t^{36}u^{12}}})^2 ?

The solution to (\sqrt[6]{sqrt(s^{24)t^{36}u^{12}}})^2 is s^4t^6u^2

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simplify (\sqrt[6]{sqrt(s^{24)t^{36}u^{12}}})^2

simplify

s^{4} t^{6} u^{2}

Solution steps

Simplify

= (s^{2} t^{3} u)^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(s^{2} t^{3} u)^{2} = (s^{2})^{2} (t^{3})^{2} u^{2}

= (s^{2})^{2} (t^{3})^{2} u^{2}

Simplify

(s^{2})^{2} : s^{4}

= s^{4} (t^{3})^{2} u^{2}

Simplify

(t^{3})^{2} : t^{6}

= s^{4} t^{6} u^{2}

3^{x} \times 2^{x}

- (x + 1)^{2}

(e^{- 3} f^{4})^{- \frac{1}{2}}

e^{- a t} \cdot cos (b t)

\frac{x ^{2 - b}}{x ^{2 + 8 x + 15}}

What is (\sqrt[6]{sqrt(s^{24)t^{36}u^{12}}})^2 ?
The solution to (\sqrt[6]{sqrt(s^{24)t^{36}u^{12}}})^2 is s^4t^6u^2