What is v^2w(x+x^2)y^2(z+z^2) ?

The solution to v^2w(x+x^2)y^2(z+z^2) is v^2wy^2(x^2+x)(z^2+z)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify v^2w(x+x^2)y^2(z+z^2)

simplify

v^{2} w (x + x^{2}) y^{2} (z + z^{2})

v^{2} w y^{2} (x^{2} + x) (z^{2} + z)

Solution steps

v^{2} w (x + x^{2}) y^{2} (z + z^{2})

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

v^{2} y^{2} = (v y)^{2}

= w (v y)^{2} (x^{2} + x) (z^{2} + z)

(v y)^{2} = v^{2} y^{2}

= v^{2} w y^{2} (x^{2} + x) (z^{2} + z)

e^{- 4 \cdot l n (x)}

\frac{5 - 2 x}{x + 3}

\frac{25 - x ^{2}}{x + 3}

\frac{5 w}{7}

\frac{6.757 4 ^{2}}{6.257 4 ^{2}}

What is v^2w(x+x^2)y^2(z+z^2) ?
The solution to v^2w(x+x^2)y^2(z+z^2) is v^2wy^2(x^2+x)(z^2+z)