What is 10xye^{-(x^2+y^2)} ?

The solution to 10xye^{-(x^2+y^2)} is (10xy)/(e^{x^2+y^2)}

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simplify 10xye^{-(x^2+y^2)}

simplify

10 x y e^{- (x^{2} + y^{2})}

\frac{10 x y}{e ^{x^{2} + y^{2}}}

Solution steps

10 x y e^{- (x^{2} + y^{2})}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= 10 \cdot \frac{1}{e ^{(x^{2} + y^{2})}} x y

Remove parentheses:

(a) = a

= 10 x y \frac{1}{e ^{x^{2} + y^{2}}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 10 x y}{e ^{x^{2} + y^{2}}}

Multiply the numbers:

1 \cdot 10 = 10

= \frac{10 x y}{e ^{x^{2} + y^{2}}}

3.6 \cdot 1 0^{- 7}

t e^{- t} u (- t)

e^{- l n (x^{3})}

e^{(- 2 x^{2})}

e^{a x} \cdot e^{a x}

What is 10xye^{-(x^2+y^2)} ?
The solution to 10xye^{-(x^2+y^2)} is (10xy)/(e^{x^2+y^2)}