What is \sqrt[3]{(4x^2+3x-2)^2} ?

The solution to \sqrt[3]{(4x^2+3x-2)^2} is (4x^2+3x-2)^{2/3}

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simplify \sqrt[3]{(4x^2+3x-2)^2}

simplify

(4 x^{2} + 3 x - 2)^{\frac{2}{3}}

Solution steps

Apply radical rule:

= ((4 x^{2} + 3 x - 2)^{2})^{\frac{1}{3}}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

= (4 x^{2} + 3 x - 2)^{2 \cdot \frac{1}{3}}

2 \cdot \frac{1}{3} = \frac{2}{3}

= (4 x^{2} + 3 x - 2)^{\frac{2}{3}}

x^{4} (x - 2)^{6} (x + 2)^{6}

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e^{- n} \cdot sin^{2} (e^{n})

(4 x^{2}) (9 y) (2 x y)

What is \sqrt[3]{(4x^2+3x-2)^2} ?
The solution to \sqrt[3]{(4x^2+3x-2)^2} is (4x^2+3x-2)^{2/3}