What is (e^{4x}-5)(e^{-2x}) ?

The solution to (e^{4x}-5)(e^{-2x}) is (e^{4x}-5)/(e^{2x)}

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simplify (e^{4x}-5)(e^{-2x})

simplify

(e^{4 x} - 5) (e^{- 2 x})

\frac{e ^{4 x} - 5}{e ^{2 x}}

Solution steps

(e^{4 x} - 5) (e^{- 2 x})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{2 x}} (e^{4 x} - 5)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( e ^{4 x} - 5 )}{e ^{2 x}}

1 \cdot (e^{4 x} - 5) = e^{4 x} - 5

= \frac{e ^{4 x} - 5}{e ^{2 x}}

0.5 \cdot 5.41 \cdot 1 0^{- 3} \cdot \frac{0.072 7 ^{2}}{0.126}

e^{- \frac{1}{3} x}

1.4 \cdot 1 0^{- 8}

- 9 x^{7} (8 x^{5})

e^{- \frac{8}{9}}

What is (e^{4x}-5)(e^{-2x}) ?
The solution to (e^{4x}-5)(e^{-2x}) is (e^{4x}-5)/(e^{2x)}