What is factor 2x^3+3x^2-23x-42 ?

The solution to factor 2x^3+3x^2-23x-42 is (x+2)(x+3)(2x-7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 2x^3+3x^2-23x-42

factor

2 x^{3} + 3 x^{2} - 23 x - 42

(x + 2) (x + 3) (2 x - 7)

Solution steps

2 x^{3} + 3 x^{2} - 23 x - 42

Use the rational root theorem

= (x + 2) \frac{2 x ^{3} + 3 x ^{2} - 23 x - 42}{x + 2}

\frac{2 x ^{3} + 3 x ^{2} - 23 x - 42}{x + 2} = 2 x^{2} - x - 21

= (x + 2) (2 x^{2} - x - 21)

Factor

2 x^{2} - x - 21 : (x + 3) (2 x - 7)

= (x + 2) (x + 3) (2 x - 7)

7 - 3 x = 5 x + 11

\frac{1}{4 + 7}

15 \cdot 6

x^{2} + 4 x = 28

(66 c + 99 d) \cdot \frac{1}{3}

What is factor 2x^3+3x^2-23x-42 ?
The solution to factor 2x^3+3x^2-23x-42 is (x+2)(x+3)(2x-7)