What is P^1(4,5)P^2(7,4)P^3(2,-4) ?

The solution to P^1(4,5)P^2(7,4)P^3(2,-4) is (4*5,)(7*4,)(2,-4)P^6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify P^1(4,5)P^2(7,4)P^3(2,-4)

simplify

P^{1} (4, 5) P^{2} (7, 4) P^{3} (2, - 4)

(4 \cdot 5,) (7 \cdot 4,) (2, - 4) P^{6}

Solution steps

P^{1} (4, 5) P^{2} (7, 4) P^{3} (2, - 4)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

P^{1} P^{2} P^{3} = P^{1 + 2 + 3}

= (4, 5) (7, 4) P^{1 + 2 + 3} (2, - 4)

Add the numbers:

1 + 2 + 3 = 6

= (4, 5) (7, 4) P^{6} (2, - 4)

(\frac{10}{3})^{3} x 0. 3^{- 1}

x^{- 6}

\frac{- 12}{- 2}

x^{- 3}

(0.5) (0.5) (\frac{1.96}{0.03})^{2}

What is P^1(4,5)P^2(7,4)P^3(2,-4) ?
The solution to P^1(4,5)P^2(7,4)P^3(2,-4) is (4*5,)(7*4,)(2,-4)P^6