What is 1>100*((9/10)^n)/((9/10)^1) ?

The solution to 1>100*((9/10)^n)/((9/10)^1) is n>log_{9/10}(9/1000)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1>100*((9/10)^n)/((9/10)^1)

1 > 100 \cdot \frac{( \frac{9}{10} ) ^{n}}{( \frac{9}{10} ) ^{1}}

n > lo g_{\frac{9}{10}} (\frac{9}{1000})

Solution steps

1 > 100 \cdot \frac{( \frac{9}{10} ) ^{n}}{( \frac{9}{10} ) ^{1}}

Switch sides

100 \cdot \frac{( \frac{9}{10} ) ^{n}}{( \frac{9}{10} ) ^{1}} < 1

Refine

100 \cdot \frac{( \frac{9}{10} ) ^{n}}{( \frac{9}{10} ) ^{1}} : \frac{1000 ( \frac{9}{10} ) ^{n}}{9}

\frac{1000 ( \frac{9}{10} ) ^{n}}{9} < 1

Multiply both sides by

9

1000 (\frac{9}{10})^{n} < 9

Divide both sides by

1000

(\frac{9}{10})^{n} < \frac{9}{1000}

Apply exponent rules

n > lo g_{\frac{9}{10}} (\frac{9}{1000})

5 x - 4 = 2 (x - 2)

x^{3} - 8 x^{2} + 2 x - 16

(0.25) (0.5) = (2) (x)

- v + 1 = 1 + 8 v

2 (3 x + 3) = 18

What is 1>100*((9/10)^n)/((9/10)^1) ?
The solution to 1>100*((9/10)^n)/((9/10)^1) is n>log_{9/10}(9/1000)