What is (2c^{3/5})(2c^{1/5}) ?

The solution to (2c^{3/5})(2c^{1/5}) is 4c^{4/5}

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simplify (2c^{3/5})(2c^{1/5})

simplify

(2 c^{\frac{3}{5}}) (2 c^{\frac{1}{5}})

4 c^{\frac{4}{5}}

Solution steps

(2 c^{\frac{3}{5}}) (2 c^{\frac{1}{5}})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2 \cdot 2 = 2^{1 + 1}

= c^{\frac{3}{5}} \cdot 2^{1 + 1} c^{\frac{1}{5}}

Add the numbers:

1 + 1 = 2

= c^{\frac{3}{5}} \cdot 2^{2} c^{\frac{1}{5}}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

c^{\frac{3}{5}} c^{\frac{1}{5}} = c^{\frac{3}{5} + \frac{1}{5}}

= 2^{2} c^{\frac{3}{5} + \frac{1}{5}}

Combine the fractions

\frac{3}{5} + \frac{1}{5} : \frac{4}{5}

= 2^{2} c^{\frac{4}{5}}

2^{2} = 4

= 4 c^{\frac{4}{5}}

x^{2} (1 - x^{2})^{2}

e e^{- x}

\frac{- 32}{8}

s^{2} (s + 2)^{2}