What is (-1)/2 sin(-3x)*e^{-2x} ?

The solution to (-1)/2 sin(-3x)*e^{-2x} is -(sin(-3x))/(2e^{2x)}

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simplify (-1)/2 sin(-3x)*e^{-2x}

simplify

\frac{- 1}{2} sin (- 3 x) \cdot e^{- 2 x}

- \frac{sin ( - 3 x )}{2 e ^{2 x}}

Solution steps

\frac{- 1}{2} sin (- 3 x) e^{- 2 x}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{- 1}{2} \cdot \frac{1}{e ^{2 x}} sin (- 3 x)

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{1}{2} \cdot \frac{1}{e ^{2 x}} sin (- 3 x)

Multiply fractions:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= - \frac{1 \cdot 1 \cdot sin ( - 3 x )}{2 e ^{2 x}}

Multiply:

1 \cdot 1 \cdot sin (- 3 x) = sin (- 3 x)

= - \frac{sin ( - 3 x )}{2 e ^{2 x}}

2.8 \cdot 1 0^{- 8}

x^{2} (x^{2} + 2)^{2}

x (x - 1)^{2} (x + 4)^{2}

x^{2} \cdot (m \cdot (m - 1) \cdot x^{m - 2})

What is (-1)/2 sin(-3x)*e^{-2x} ?
The solution to (-1)/2 sin(-3x)*e^{-2x} is -(sin(-3x))/(2e^{2x)}