What is (x^5-y^4)^2*(x^3y-y^4)^2 ?

The solution to (x^5-y^4)^2*(x^3y-y^4)^2 is (x^5-y^4)^2(-y^4+x^3y)^2

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simplify (x^5-y^4)^2*(x^3y-y^4)^2

simplify

(x^{5} - y^{4})^{2} \cdot (x^{3} y - y^{4})^{2}

(x^{5} - y^{4})^{2} (- y^{4} + x^{3} y)^{2}

Solution steps

(x^{5} - y^{4})^{2} (x^{3} y - y^{4})^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(x^{5} - y^{4})^{2} (- y^{4} + x^{3} y)^{2} = ((x^{5} - y^{4}) (- y^{4} + x^{3} y))^{2}

= ((x^{5} - y^{4}) (- y^{4} + x^{3} y))^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= (x^{5} - y^{4})^{2} (- y^{4} + x^{3} y)^{2}

(7 x y^{2}) \cdot (2 y)

(e^{- 3 x}) (2 e^{2 x})

(5 x^{3}) (4 x^{7})

e^{- \frac{1}{0.5}}

What is (x^5-y^4)^2*(x^3y-y^4)^2 ?
The solution to (x^5-y^4)^2*(x^3y-y^4)^2 is (x^5-y^4)^2(-y^4+x^3y)^2