What is e^{-4(1/3)}(-1+12(1/3)) ?

The solution to e^{-4(1/3)}(-1+12(1/3)) is 3/(e^{4/3)}

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simplify e^{-4(1/3)}(-1+12(1/3))

simplify

e^{- 4 (\frac{1}{3})} (- 1 + 12 (\frac{1}{3}))

\frac{3}{e ^{\frac{4}{3}}}

Decimal Notation

0.79079 \dots

Solution steps

e^{- 4 (\frac{1}{3})} (- 1 + 12 (\frac{1}{3}))

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{4 \cdot \frac{1}{3}}} (12 \cdot \frac{1}{3} - 1)

\frac{1}{e ^{4 \cdot \frac{1}{3}}} = \frac{1}{e ^{\frac{4}{3}}}

= \frac{1}{e ^{\frac{4}{3}}} (12 \cdot \frac{1}{3} - 1)

12 \cdot \frac{1}{3} = 4

= \frac{1}{e ^{\frac{4}{3}}} (4 - 1)

Add/Subtract the numbers:

- 1 + 4 = 3

= 3 \cdot \frac{1}{e ^{\frac{4}{3}}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 3}{e ^{\frac{4}{3}}}

Multiply the numbers:

1 \cdot 3 = 3

= \frac{3}{e ^{\frac{4}{3}}}

(2 y^{2}) (3 y w)

5.46 \cdot 1 0^{- 12}

3 x^{2} y^{2} z (7 x^{2} + 2 y + z + 4 w)

(6 - 7) (6 - 7)

What is e^{-4(1/3)}(-1+12(1/3)) ?
The solution to e^{-4(1/3)}(-1+12(1/3)) is 3/(e^{4/3)}