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Popular >

simplify g(r,s)reen^'s

Solution

simplify

g (r, s) ree n^{^{'}} s

Solution

e^{2} n^{'} rs g (, rs)

Solution steps

g (r, s) ree n^{^{'}} s

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

ee = e^{1 + 1}

= g (r, s) r e^{1 + 1} n^{^{^{'}}} s

Add the numbers:

1 + 1 = 2

= g (r, s) r e^{2} n^{^{^{'}}} s

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1.9 \cdot 1 0^{- 3} \cdot \frac{2}{2}

Frequently Asked Questions (FAQ)

What is g(r,s)reen^'s ?
The solution to g(r,s)reen^'s is e^2n^'rsg(,rs)