What is (sqrt(9-x))/(sqrt(x^2-2x)) ?

The solution to (sqrt(9-x))/(sqrt(x^2-2x)) is sqrt((-x+9)/(x^2-2x))

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simplify (sqrt(9-x))/(sqrt(x^2-2x))

simplify

\frac{9 - x}{x ^{2} - 2 x}

\frac{- x + 9}{x ^{2} - 2 x}

Solution steps

\frac{9 - x}{x ^{2} - 2 x}

Apply radical rule:

\frac{a}{b} = \frac{a}{b}

\frac{9 - x}{x ^{2} - 2 x} = \frac{9 - x}{x ^{2} - 2 x}

= \frac{9 - x}{x ^{2} - 2 x}

e^{- 20 x}

\frac{8 ^{2} - 6 ^{2}}{7}

- e^{- \frac{x ^{2}}{50}}

\frac{- 18}{- 3}

1.25 \cdot 1 0^{- 10}

What is (sqrt(9-x))/(sqrt(x^2-2x)) ?
The solution to (sqrt(9-x))/(sqrt(x^2-2x)) is sqrt((-x+9)/(x^2-2x))