What is 25000(1+((0.085)/4))^{-(4(1))} ?

The solution to 25000(1+((0.085)/4))^{-(4(1))} is (25000*800^4)/(817^4)

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simplify 25000(1+((0.085)/4))^{-(4(1))}

simplify

25000 (1 + (\frac{0.085}{4}))^{- (4 (1))}

\frac{25000 \cdot 80 0 ^{4}}{81 7 ^{4}}

Decimal Notation

22983.26531 \dots

Solution steps

25000 (1 + (\frac{0.085}{4}))^{- (4 (1))}

(1 + (\frac{0.085}{4}))^{- (4 (1))} = (1 + \frac{0.085}{4})^{- 4 \cdot 1}

= 25000 (1 + \frac{0.085}{4})^{- 4 \cdot 1}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(1 + \frac{0.085}{4})^{- 4 \cdot 1} = \frac{1}{( 1 + \frac{0.085}{4} ) ^{4 \cdot 1}}

= 25000 \cdot \frac{1}{( 1 + \frac{0.085}{4} ) ^{4 \cdot 1}}

(1 + \frac{0.085}{4})^{4 \cdot 1} = \frac{81 7 ^{4}}{80 0 ^{4}}

= 25000 \cdot \frac{1}{\frac{81 7 ^{4}}{80 0 ^{4}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= 25000 \cdot \frac{80 0 ^{4}}{81 7 ^{4}}

25000 \cdot \frac{80 0 ^{4}}{81 7 ^{4}} = \frac{25000 \cdot 80 0 ^{4}}{81 7 ^{4}}

= \frac{25000 \cdot 80 0 ^{4}}{81 7 ^{4}}

x + 1 1 + \frac{1}{x + 1}

(- 1)^{n} (- 3)^{n}

1.6 \times 1 0^{- 4}

What is 25000(1+((0.085)/4))^{-(4(1))} ?
The solution to 25000(1+((0.085)/4))^{-(4(1))} is (25000*800^4)/(817^4)