What is (\sqrt[5]{a^{-4}*b^7})^2 ?

The solution to (\sqrt[5]{a^{-4}*b^7})^2 is (b^2\sqrt[5]{b^4})/(a\sqrt[5]{a^3)}

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simplify (\sqrt[5]{a^{-4}*b^7})^2

simplify

Solution steps

Simplify

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

Simplify

= \frac{b ^{\frac{14}{5}}}{a ^{\frac{8}{5}}}

Combine same powers :

Apply radical rule:

assuming

a \geq 0, b \geq 0

Simplify

e^{- 1} \cdot e^{- 2}

((1 - x^{2})^{\frac{3}{2}})^{2}

e^{- \frac{0.129}{0.8}}

(1.2 \cdot 1 0^{- 3}) (6.7 \cdot 1 0^{- 7})

What is (\sqrt[5]{a^{-4}*b^7})^2 ?
The solution to (\sqrt[5]{a^{-4}*b^7})^2 is (b^2\sqrt[5]{b^4})/(a\sqrt[5]{a^3)}