What is (f\circ f)sqrt(x+1) ?

The solution to (f\circ f)sqrt(x+1) is \circ f^2sqrt(x+1)

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simplify (f\circ f)sqrt(x+1)

simplify

(f \circ f) x + 1

\circ f^{2} x + 1

Solution steps

(f \circ f) x + 1

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

ff = f^{1 + 1}

= \circ f^{1 + 1} x + 1

Add the numbers:

1 + 1 = 2

= \circ f^{2} x + 1

e^{e} \cdot e

(x - 3)^{2} (x - 5)^{2}

e^{- 1.05}

(e^{x} + 1) (e^{x} + 1)

What is (f\circ f)sqrt(x+1) ?
The solution to (f\circ f)sqrt(x+1) is \circ f^2sqrt(x+1)