What is (b^{11}d^9z^7)(dr^4z^{18})(a^2b^9z) ?

The solution to (b^{11}d^9z^7)(dr^4z^{18})(a^2b^9z) is b^{20}d^{10}a^2z^{26}r^4

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simplify (b^{11}d^9z^7)(dr^4z^{18})(a^2b^9z)

simplify

(b^{11} d^{9} z^{7}) (d r^{4} z^{18}) (a^{2} b^{9} z)

b^{20} d^{10} a^{2} z^{26} r^{4}

Solution steps

(b^{11} d^{9} z^{7}) (d r^{4} z^{18}) (a^{2} b^{9} z)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

b^{11} b^{9} = b^{11 + 9}

= d^{9} z^{7} d r^{4} z^{18} a^{2} b^{11 + 9} z

Add the numbers:

11 + 9 = 20

= d^{9} z^{7} d r^{4} z^{18} a^{2} b^{20} z

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

d^{9} d = d^{9 + 1}

= z^{7} d^{9 + 1} r^{4} z^{18} a^{2} b^{20} z

Add the numbers:

9 + 1 = 10

= z^{7} d^{10} r^{4} z^{18} a^{2} b^{20} z

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

z^{7} z^{18} z = z^{7 + 18 + 1}

= d^{10} r^{4} a^{2} b^{20} z^{7 + 18 + 1}

Add the numbers:

7 + 18 + 1 = 26

= d^{10} r^{4} a^{2} b^{20} z^{26}

\frac{3}{14} \cdot \frac{14}{14}

1 - x \times 1 + x

\frac{1}{( 2 π ) ^{\frac{1}{2}}} e^{- \frac{1}{2} \cdot 9}

- 3 e^{- \frac{3}{2}}

What is (b^{11}d^9z^7)(dr^4z^{18})(a^2b^9z) ?
The solution to (b^{11}d^9z^7)(dr^4z^{18})(a^2b^9z) is b^{20}d^{10}a^2z^{26}r^4