What is 4(6x^{10}y^5z)(10x^3y^4z^2) ?

The solution to 4(6x^{10}y^5z)(10x^3y^4z^2) is 240x^{13}y^9z^3

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simplify 4(6x^{10}y^5z)(10x^3y^4z^2)

simplify

4 (6 x^{10} y^{5} z) (10 x^{3} y^{4} z^{2})

240 x^{13} y^{9} z^{3}

Solution steps

4 (6 x^{10} y^{5} z) (10 x^{3} y^{4} z^{2})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x^{10} x^{3} = x^{10 + 3}

= 4 \cdot 6 y^{5} z \cdot 10 x^{10 + 3} y^{4} z^{2}

Add the numbers:

10 + 3 = 13

= 4 \cdot 6 y^{5} z \cdot 10 x^{13} y^{4} z^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

y^{5} y^{4} = y^{5 + 4}

= 4 \cdot 6 z \cdot 10 x^{13} y^{5 + 4} z^{2}

Add the numbers:

5 + 4 = 9

= 4 \cdot 6 z \cdot 10 x^{13} y^{9} z^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

z z^{2} = z^{1 + 2}

= 4 \cdot 6 \cdot 10 x^{13} y^{9} z^{1 + 2}

Add the numbers:

1 + 2 = 3

= 4 \cdot 6 \cdot 10 x^{13} y^{9} z^{3}

Multiply the numbers:

4 \cdot 6 \cdot 10 = 240

= 240 x^{13} y^{9} z^{3}

4.5 \cdot 1 0^{- 7}

12 e^{- 12 (1)}

523961.66 (1 + \frac{0.12}{12})^{- 24}

8.85 \cdot 1 0^{- 12} (5) (\frac{1}{6 \cdot 1 0 ^{7}} - \frac{1}{1 0 ^{7}})

(e^{2 x})^{3}

What is 4(6x^{10}y^5z)(10x^3y^4z^2) ?
The solution to 4(6x^{10}y^5z)(10x^3y^4z^2) is 240x^{13}y^9z^3