What is (r+1)^2(r-sqrt(2))^2(r+sqrt(2))^2(r-1) ?

The solution to (r+1)^2(r-sqrt(2))^2(r+sqrt(2))^2(r-1) is (r+1)^2(r^4-4r^2+4)(r-1)

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simplify (r+1)^2(r-sqrt(2))^2(r+sqrt(2))^2(r-1)

simplify

(r + 1)^{2} (r - 2)^{2} (r + 2)^{2} (r - 1)

(r + 1)^{2} (r^{4} - 4 r^{2} + 4) (r - 1)

Solution steps

(r + 1)^{2} (r - 2)^{2} (r + 2)^{2} (r - 1)

Expand

(r - 2)^{2} : r^{2} - 22 r + 2

= (r + 1)^{2} (r^{2} - 22 r + 2) (r + 2)^{2} (r - 1)

Expand

(r + 2)^{2} : r^{2} + 22 r + 2

= (r + 1)^{2} (r^{2} - 22 r + 2) (r^{2} + 22 r + 2) (r - 1)

Expand

(r^{2} - 22 r + 2) (r^{2} + 22 r + 2) : r^{4} - 4 r^{2} + 4

= (r + 1)^{2} (r^{4} - 4 r^{2} + 4) (r - 1)

1.15 \times 1 0^{- 3}

e^{- 4 π}

(a^{4} + 5 a^{3} + 2 a^{2} - 6 a + 4) (a + 2)^{- 1}

x \cdot 1 - x^{2}

What is (r+1)^2(r-sqrt(2))^2(r+sqrt(2))^2(r-1) ?
The solution to (r+1)^2(r-sqrt(2))^2(r+sqrt(2))^2(r-1) is (r+1)^2(r^4-4r^2+4)(r-1)