What are the solutions to the equation 3^2+b^2=5^2 ?

The solutions to the equation 3^2+b^2=5^2 are b=4,b=-4

Find the zeros of 3^2+b^2=5^2

The zeros of 3^2+b^2=5^2 are b=4,b=-4

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3^{2} + b^{2} = 5^{2}

b = 4, b = - 4

Solution steps

3^{2} + b^{2} = 5^{2}

Move

3^{2}

to the right side

b^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 16, b = - 16

16 = 4

- 16 = - 4

b = 4, b = - 4

(1 + \frac{0.12}{12})^{12} - 1

14 m^{2} + 17 m - 22

\frac{x - 1}{2} + \frac{2 x + 3}{4} = 1

\frac{4}{9} \cdot \frac{3}{7} \cdot \frac{5}{2}

4 x^{2} = 32 x

What are the solutions to the equation 3^2+b^2=5^2 ?
The solutions to the equation 3^2+b^2=5^2 are b=4,b=-4
Find the zeros of 3^2+b^2=5^2
The zeros of 3^2+b^2=5^2 are b=4,b=-4