What is 2(x-1)^2(x+1)^2(x-3) ?

The solution to 2(x-1)^2(x+1)^2(x-3) is 2(x-1)^2(x+1)^2(x-3)

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simplify 2(x-1)^2(x+1)^2(x-3)

simplify

2 (x - 1)^{2} (x + 1)^{2} (x - 3)

2 (x - 1)^{2} (x + 1)^{2} (x - 3)

Solution steps

2 (x - 1)^{2} (x + 1)^{2} (x - 3)

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(x - 1)^{2} (x + 1)^{2} = ((x - 1) (x + 1))^{2}

= 2 ((x - 1) (x + 1))^{2} (x - 3)

((x - 1) (x + 1))^{2} = (x - 1)^{2} (x + 1)^{2}

= 2 (x - 1)^{2} (x + 1)^{2} (x - 3)

\frac{e ^{x^{2}}}{e ^{x^{2}}}

18 e^{- 0.21}

(3 s t^{2} u^{9} v^{2}) (2 s t^{3} u v^{3})

2 e^{- \frac{1}{10}}

What is 2(x-1)^2(x+1)^2(x-3) ?
The solution to 2(x-1)^2(x+1)^2(x-3) is 2(x-1)^2(x+1)^2(x-3)