What is (x^2+y)^2(x^2-y)^2(y^4+y^2) ?

The solution to (x^2+y)^2(x^2-y)^2(y^4+y^2) is (x^2+y)^2(x^2-y)^2(y^4+y^2)

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simplify (x^2+y)^2(x^2-y)^2(y^4+y^2)

simplify

(x^{2} + y)^{2} (x^{2} - y)^{2} (y^{4} + y^{2})

(x^{2} + y)^{2} (x^{2} - y)^{2} (y^{4} + y^{2})

Solution steps

(x^{2} + y)^{2} (x^{2} - y)^{2} (y^{4} + y^{2})

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(x^{2} + y)^{2} (x^{2} - y)^{2} = ((x^{2} + y) (x^{2} - y))^{2}

= ((x^{2} + y) (x^{2} - y))^{2} (y^{4} + y^{2})

((x^{2} + y) (x^{2} - y))^{2} = (x^{2} + y)^{2} (x^{2} - y)^{2}

= (x^{2} + y)^{2} (x^{2} - y)^{2} (y^{4} + y^{2})

(25) (35)

\frac{1}{2} (1.67 \cdot 1 0^{- 27}) (1.3 \cdot 1 0^{6})^{2}

\frac{1}{2} e^{\frac{x}{2}} \cdot e^{- x}

6 e^{- 6}

What is (x^2+y)^2(x^2-y)^2(y^4+y^2) ?
The solution to (x^2+y)^2(x^2-y)^2(y^4+y^2) is (x^2+y)^2(x^2-y)^2(y^4+y^2)