What are the solutions to the equation x^2+18x+82=0 ?

The solutions to the equation x^2+18x+82=0 are x=-9+i,x=-9-i

Find the zeros of x^2+18x+82=0

The zeros of x^2+18x+82=0 are x=-9+i,x=-9-i

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x^{2} + 18 x + 82 = 0

x = - 9 + i, x = - 9 - i

Solution steps

x^{2} + 18 x + 82 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 82}{2 \cdot 1}

Simplify

1 8^{2} - 4 \cdot 1 \cdot 82 : 2 i

x_{1, 2} = \frac{- 18 \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 2 i}{2 \cdot 1}, x_{2} = \frac{- 18 - 2 i}{2 \cdot 1}

x = \frac{- 18 + 2 i}{2 \cdot 1} : - 9 + i

x = \frac{- 18 - 2 i}{2 \cdot 1} : - 9 - i

The solutions to the quadratic equation are:

x = - 9 + i, x = - 9 - i

∣ 8 - 16 x ∣ < - 13

- x^{2} + x + 20

∣ 2 a + 8 ∣ = ∣ 3 a - 4 ∣

5200 \cdot 0.0085 \cdot x = 663

(2.2) 2^{- n} < 1 0^{- 3}

What are the solutions to the equation x^2+18x+82=0 ?
The solutions to the equation x^2+18x+82=0 are x=-9+i,x=-9-i
Find the zeros of x^2+18x+82=0
The zeros of x^2+18x+82=0 are x=-9+i,x=-9-i