What is \sqrt[3]{25}*\sqrt[6]{4}^2 ?

The solution to \sqrt[3]{25}*\sqrt[6]{4}^2 is cube root of 100

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simplify \sqrt[3]{25}*\sqrt[6]{4}^2

simplify

325 \cdot 64^{2}

3100

Decimal

4.64158 \dots

Solution steps

325 (64)^{2}

(64)^{2} = 34

= 32534

Apply radical rule:

n a n b = n ab, a \geq 0, b \geq 0

32534 = 3 25 \cdot 4

= 3 25 \cdot 4

Multiply the numbers:

25 \cdot 4 = 100

= 3100

(3 x^{\frac{1}{2}}) (3 x^{\frac{5}{2}})

f (x) e^{- x}

e^{x} \times e^{- 2 x}

- \frac{1}{2} e^{- \frac{x}{2}} \cdot e^{\frac{x}{2}}

e^{- 1 0^{2}}

What is \sqrt[3]{25}*\sqrt[6]{4}^2 ?
The solution to \sqrt[3]{25}*\sqrt[6]{4}^2 is cube root of 100