What is sqrt((3x^2+2)\sqrt{6x-7)} ?

The solution to sqrt((3x^2+2)\sqrt{6x-7)} is sqrt(\sqrt{6x-7)}sqrt(3x^2+2)

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simplify sqrt((3x^2+2)\sqrt{6x-7)}

simplify

(3 x^{2} + 2) 6 x - 7

6 x - 7 3 x^{2} + 2

Solution steps

(3 x^{2} + 2) 6 x - 7

Apply radical rule:

ab = a b,

assuming

a \geq 0, b \geq 0

(3 x^{2} + 2) 6 x - 7 = 3 x^{2} + 2 6 x - 7

= 3 x^{2} + 2 6 x - 7

= 6 x - 7 3 x^{2} + 2

(3 - 1)^{4} (3 + 1)^{4}

(5 a^{2} b^{3}) (3 ab)

2300 e^{- 0.01 (5)}

What is sqrt((3x^2+2)\sqrt{6x-7)} ?
The solution to sqrt((3x^2+2)\sqrt{6x-7)} is sqrt(\sqrt{6x-7)}sqrt(3x^2+2)