What is (\sqrt[5]{x^4y^2})^{20} ?

The solution to (\sqrt[5]{x^4y^2})^{20} is x^{16}y^8

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simplify (\sqrt[5]{x^4y^2})^{20}

simplify

x^{16} y^{8}

Solution steps

Rewrite

20

5 \cdot 4

Apply exponent rule:

a^{b c} = (a^{b})^{c},

assuming

a \geq 0

Apply exponent rule:

assuming

n i s o dd or a \geq 0

= (x^{4} y^{2})^{4}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(x^{4} y^{2})^{4} = (x^{4})^{4} (y^{2})^{4}

= (x^{4})^{4} (y^{2})^{4}

Simplify

(x^{4})^{4} : x^{16}

= x^{16} (y^{2})^{4}

Simplify

(y^{2})^{4} : y^{8}

= x^{16} y^{8}

(x^{2} - 9 - 4) (x^{2} - 9 - 4)

- 6 a^{2} b^{4} c^{2} (- 6 a b^{4} c^{2} + 4 a b^{4} + 9 a^{2} b^{4} c^{2})

2 \cdot (2 \cdot 1 0^{- 5}) \cdot (1.8 \cdot 1 0^{- 4}) \cdot (165 - 20)

(26) (2)

sin (4 t) e^{- s t}

What is (\sqrt[5]{x^4y^2})^{20} ?
The solution to (\sqrt[5]{x^4y^2})^{20} is x^{16}y^8